欧拉回路(Eulerian path/circuit)
- DFS 版本(适用于有向图和无向图,代码为无向图)
- 无递归版本 - 有向图
- 无递归版本 - 无向图
DFS 版本
#include <cstdio>
#include <vector>
#include <algorithm>
const int MAXN = 100005;
const int MAXM = 200005;
struct Edge;
struct Node {
Edge *e, *curr;
int deg;
} N[MAXN];
struct Edge {
Node *u, *v;
Edge *next, *rev;
bool used;
Edge() {}
Edge(Node *u, Node *v) : u(u), v(v), next(u->e), used(false) {}
} _pool[MAXM << 1], *_curr = _pool;
void addEdge(int u, int v) {
N[u].e = new (_curr++) Edge(&N[u], &N[v]);
N[v].e = new (_curr++) Edge(&N[v], &N[u]);
N[u].e->rev = N[v].e;
N[v].e->rev = N[u].e;
++N[u].deg;
++N[v].deg;
}
namespace Euler {
std::vector<Edge *> path;
void dfs(Node *u) {
for (Edge *&e = u->curr; e; e = e->next) if (!e->used) {
e->used = e->rev->used = true;
dfs(e->v);
path.push_back(e);
}
}
bool solve(int n) {
int cnt = 0;
for (int i = 1; i <= n; i++) cnt += N[i].deg % 2;
if (cnt > 2) return false;
for (int i = 1; i <= n; i++) N[i].curr = N[i].e;
int s = -1;
if (cnt) for (int i = 1; i <= n; i++) if (N[i].deg % 2) {
s = i;
break;
}
s = (s == -1 ? 1 : s);
dfs(&N[s]);
std::reverse(path.begin(), path.end());
return true;
}
}
int main() {
int n, m;
scanf("%d %d", &n, &m);
for (int i = 0, u, v; i < m; i++) {
scanf("%d %d", &u, &v);
addEdge(u, v);
}
if (Euler::solve(n)) {
printf("%d", Euler::path[0]->u - N);
for (int i = 0; i < Euler::path.size(); i++) {
printf(" -> %d", Euler::path[i]->v - N);
}
puts("");
} else {
puts("-1");
}
return 0;
}
有向图欧拉回路
#include <cstdio>
#include <vector>
#include <stack>
#include <algorithm>
const int MAXN = 100005;
const int MAXM = 400005;
struct Edge;
struct Node {
Edge *e, *curr;
int ideg, odeg;
} N[MAXN];
struct Edge {
Node *u, *v;
Edge *next;
Edge() {}
Edge(Node *u, Node *v) : u(u), v(v), next(u->e) {}
} _pool[MAXM], *_curr = _pool;
void addEdge(int u, int v) {
N[u].e = new (_curr++) Edge(&N[u], &N[v]);
++N[u].odeg;
++N[v].ideg;
}
namespace Hierholzer {
std::stack<Node *> currPath;
std::vector<Node *> euler;
void hierholzer(int s) {
currPath.push(&N[s]);
Node *u = &N[s];
do {
if (u->odeg == 0) {
euler.push_back(currPath.top());
currPath.pop();
if (!currPath.empty()) u = currPath.top();
} else {
Node *v = u->curr->v;
u->curr = u->curr->next;
--u->odeg;
u = v;
currPath.push(u);
}
} while (!currPath.empty());
}
bool solve(int n) {
int cntS = 0, cntT = 0;
for (int i = 1; i <= n; i++) {
if (N[i].ideg + 1 == N[i].odeg) ++cntS;
else if (N[i].odeg + 1 == N[i].ideg) ++cntT;
else if (N[i].ideg != N[i].odeg) return false;
}
if (cntS > 1 || cntT > 1) return false;
int s = -1;
for (int i = 1; i <= n; i++) {
if (N[i].ideg + 1 == N[i].odeg) s = i;
N[i].curr = N[i].e;
}
s = (s == -1 ? 1 : s);
hierholzer(s);
return true;
}
}
int main() {
int n, m;
scanf("%d %d", &n, &m);
for (int i = 0, u, v; i < m; i++) {
scanf("%d %d", &u, &v);
addEdge(u, v);
}
if (Hierholzer::solve(n)) {
for (int i = Hierholzer::euler.size() - 1; i >= 0; i--) {
printf("%d", Hierholzer::euler[i] - N);
if (i) printf(" -> ");
}
puts("");
} else {
puts("-1");
}
return 0;
}
无向图欧拉回路
#include <cstdio>
#include <list>
#include <vector>
#include <stack>
#include <algorithm>
const int MAXN = 100005;
const int MAXM = 400005;
struct Edge;
struct Node {
std::list<Edge> e;
int deg;
} N[MAXN];
struct Edge {
Node *u, *v;
std::list<Edge>::iterator rev;
Edge() {}
Edge(Node *u, Node *v) : u(u), v(v) {}
};
void addEdge(int u, int v) {
N[u].e.emplace_front(&N[u], &N[v]);
N[v].e.emplace_front(&N[v], &N[u]);
N[u].e.front().rev = N[v].e.begin();
N[v].e.front().rev = N[u].e.begin();
++N[u].deg;
++N[v].deg;
}
namespace Hierholzer {
std::stack<Node *> currPath;
std::vector<Node *> euler;
void hierholzer(int s) {
currPath.push(&N[s]);
Node *u = &N[s];
do {
if (u->deg == 0) {
euler.push_back(currPath.top());
currPath.pop();
if (!currPath.empty()) u = currPath.top();
} else {
Node *v = u->e.front().v;
v->e.erase(u->e.front().rev);
u->e.erase(u->e.begin());
--u->deg;
--v->deg;
u = v;
currPath.push(u);
}
} while (!currPath.empty());
}
bool solve(int n) {
int cnt = 0;
for (int i = 1; i <= n; i++) if (N[i].deg % 2) ++cnt;
if (cnt > 2) return false;
int s = -1;
if (cnt) for (int i = 1; i <= n; i++) if (N[i].deg % 2) {
s = i;
break;
}
s = (s == -1 ? 1 : s);
hierholzer(s);
return true;
}
}
int main() {
int n, m;
scanf("%d %d", &n, &m);
for (int i = 0, u, v; i < m; i++) {
scanf("%d %d", &u, &v);
addEdge(u, v);
}
if (Hierholzer::solve(n)) {
for (int i = Hierholzer::euler.size() - 1; i >= 0; i--) {
printf("%d", Hierholzer::euler[i] - N);
if (i) printf(" -> ");
}
puts("");
} else {
puts("-1");
}
return 0;
}